Ex 12.1, 2 - Minimise Z = -3x + 4y subject to x + 2y < 8 - Linear equations given - Bounded

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  1. Chapter 12 Class 12 Linear Programming
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Ex 12.1, 2 Solve the following Linear Programming Problems graphically: Minimise Z = – 3x + 4 y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0. Minimize Z = −3x + 4y Subject to x + 2y ≤ 8 3x + 2y ≤ 12 x ≥ 0, y ≥ 0 Hence, Z = –12 is minimum at (4, 0)

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