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Misc 10 - Solve 5(2x - 7) - 3(2x + 3) <= 0, 2x + 19 < 6x + 47

Misc 10 - Chapter 6 Class 11 Linear Inequalities - Part 2

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Misc 10 Solve the inequalities and represent the solution graphically on number line: 5(2x – 7) – 3(2x + 3) ≤ 0, 2x + 19 ≤ 6x + 47 Solving 5(2x – 7) – 3(2x + 3) ≤ 0 10x – 35 – 6x – 9 ≤ 0 4x – 44 ≤ 0 4(x – 11) ≤ 0 x – 11 ≤ 0/4 x – 11 ≤ 0 x ≤ 11 Solving 2x + 19 ≤ 6x + 47 2x – 6x ≤ 47 – 19 –4x ≤ 28 –x ≤ 28/4 –x ≤ 7 Since x is negative, we multiply both sides by −1 & change the signs (– 1) × (−x) ≥ (–1) × (7) x ≥ −7 Our equations are x ≤ 11 & x ≥ −7 The graphical representation is Here 11 & −7 are included in the shaded graph The solution of the system of equations is –7 ≤ x ≤ 11

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.