# Misc 10 - Chapter 6 Class 11 Linear Inequalities (Term 2)

Last updated at Feb. 17, 2020 by Teachoo

Last updated at Feb. 17, 2020 by Teachoo

Transcript

Misc 10 Solve the inequalities and represent the solution graphically on number line: 5(2x – 7) – 3(2x + 3) ≤ 0, 2x + 19 ≤ 6x + 47 Solving 5(2x – 7) – 3(2x + 3) ≤ 0 10x – 35 – 6x – 9 ≤ 0 4x – 44 ≤ 0 4(x – 11) ≤ 0 x – 11 ≤ 0/4 x – 11 ≤ 0 x ≤ 11 Solving 2x + 19 ≤ 6x + 47 2x – 6x ≤ 47 – 19 –4x ≤ 28 –x ≤ 28/4 –x ≤ 7 Since x is negative, we multiply both sides by −1 & change the signs (– 1) × (−x) ≥ (–1) × (7) x ≥ −7 Our equations are x ≤ 11 & x ≥ −7 The graphical representation is Here 11 & −7 are included in the shaded graph The solution of the system of equations is –7 ≤ x ≤ 11

Chapter 6 Class 11 Linear Inequalities (Term 2)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.