Misc 5 - Chapter 6 Class 11 Linear Inequalities (Term 2)

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Misc 5 Solve the inequality −12 < 4 −3𝑥/(−5) ≤ 2 −12 < 4 −3𝑥/(−5) ≤ 2 Subtracting 4 all sides (Eliminating 4) – 12 – 4 < 4 − 3𝑥/(−5) – 4 ≤ 2 – 4 −16 < −3𝑥/(−5) ≤ −2 −16 < 3𝑥/5 ≤ −2 Multiplying 5 all sides (Eliminating 4) −16 × 5 < 3𝑥/5 × 5 ≤ −2 × 5 –80 < 3x ≤ –10 Dividing 3 all sides (Eliminating 3) (−80)/3 < 3𝑥/3 ≤ (−10)/3 (−80)/3 < 𝑥 ≤ (−10)/3 Thus, x is a real number which is less than or equal to (−10)/3 and greater than (−80)/3 Hence, x ∈ ((−𝟖𝟎)/𝟑,(−𝟏𝟎)/𝟑] is the solution