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Theorem 6.8 - Class 9th - Exterior angle is equal to sum of two interior opposite angles. - Triangle - Properties

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  1. Chapter 6 Class 9 Lines and Angles
  2. Serial order wise
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Theorem 6.8 :- If a side of a triangle is produced, then the exterior angle so formed is equal to the sum of the two interior opposite angles. Given :- A △PQR ,QR is produced to point S. where ∠PRS is exterior angle of △PQR. To Prove :- ∠4 = ∠1 + ∠2 Proof:- From (1) and (2) ∠ 3 + ∠ 4 = ∠ 1 + ∠ 2 + ∠ 3 ∠4 = ∠1 + ∠2 ∠PRS = ∠RPQ + ∠PQR Hence, exterior angle is sum of two opposite interior angles. Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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