

Binomial Distribution
Ex 13.5, 12 Deleted for CBSE Board 2022 Exams
Ex 13.5, 2 Deleted for CBSE Board 2022 Exams
Ex 13.5, 4 Important Deleted for CBSE Board 2022 Exams
Ex 13.5, 9 Deleted for CBSE Board 2022 Exams
Ex 13.5, 6 Important Deleted for CBSE Board 2022 Exams
Ex 13.5, 11 Deleted for CBSE Board 2022 Exams
Ex 13.5, 14 (MCQ) Important Deleted for CBSE Board 2022 Exams
Ex 13.5, 15 (MCQ) Important Deleted for CBSE Board 2022 Exams
Example 32 Important Deleted for CBSE Board 2022 Exams
Ex 13.5, 13 Important Deleted for CBSE Board 2022 Exams
Ex 13.5, 3 Important Deleted for CBSE Board 2022 Exams
Misc 6 Important Deleted for CBSE Board 2022 Exams
Misc 7 Important
Ex 13.5, 7 Important Deleted for CBSE Board 2022 Exams
Example 31 Important Deleted for CBSE Board 2022 Exams
Ex 13.5, 5 Deleted for CBSE Board 2022 Exams
Ex 13.5, 10 Important Deleted for CBSE Board 2022 Exams
Misc 5 Important Deleted for CBSE Board 2022 Exams
Misc 9 Deleted for CBSE Board 2022 Exams
Misc 4 Deleted for CBSE Board 2022 Exams
Misc 10 Important
Example 35 Deleted for CBSE Board 2022 Exams
Ex 13.5, 8 Deleted for CBSE Board 2022 Exams
Example 34 Deleted for CBSE Board 2022 Exams You are here
Binomial Distribution
Example 34 Find the mean of the Binomial distribution B(4, 1/3) B(4, 1/3) means Here, n = 4, p = 1/3 So, q = 1 − 1/3 = 2/3 Hence, P (X = x) = 4Cx (𝟏/𝟑)^𝒙 (𝟐/𝟑)^(𝟒−𝒙) Mean of distribution = P (X = x) = 4Cx (1/3)^𝑥 (2/3)^(4−𝑥) Mean = = 0 + 1 × 4C1 (1/3)^1 (2/3)^3+ 2 × 4C2 (1/3)^2 (2/3)^2 + 3 × 4C3 (1/3)^3 (2/3) + 4 × 4C4 (1/3)^4 (2/3)^0 = 4 × 1/3 × 8/27 + 2 × 6 × 1/9 × 4/9 + 3 × 4 × 1/27 × 2/3 + 4 × 1/3^4 × 1 = 32/81+48/81+24/81+4/81 = 108/81 = 𝟒/𝟑