A coconut of mass 1.5 kg falls from the top of a coconut tree onto the wet sand on a beach. The height of the tree is 10 m. On impact, the coconut comes to rest by making a depression in the sand. (i) Calculate the velocity of the coconut just before it hits the sand. (ii) Assume that the average resistive force of sand is 3000 N and all of the coconut's energy is used to create the depression in the sand. Calculate the depth of the depression the coconut makes in the sand. Assume g = 10 m s⁻².

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(i) v
= 2gh
= 2 × 10 × 10
= 200 ≈ 14.1 m s -1
.

(ii) Energy at impact = mgh
= 1.5 × 10 × 10
= 150 J
. This equals work done against the sand = F × d :

3000 × d
= 150
⇒ d
= 0.05 m
= 5 cm
.

The falling coconut
(i) Falling 10 m from the tree
all the PE becomes KE: 1 2 mv 2 = mgh
Solve for v
v
= 2gh
= 2 × 10 × 10
= 14.1 m s -1
(ii) All that energy makes the depression
energy = mgh
= 1.5 × 10 × 10
= 150 J
The sand resists with 3000 N over a depth d
3000 × d = 150
Depth of the depression d = 0.05 m = 5 cm
← Back to: 7.4.3 Conservation of mechanical energy
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