Question 11 — The velocity-time graph of an - Questions at the end of the chapter - Chapter 6 - How Forces Affect Motion (Exploration)

Last updated at July 16, 2026 by

The velocity-time graph of an object of mass 10 kg moving along a straight line is shown in Fig. 6.41. Calculate the force acting on the object by using the graph.
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From the graph, velocity rises from 10 m s −1 to 30 m s −1 in 8 s (a straight line), so the acceleration is

a = 30 - 10 8 = 20 8 = 2.5 m s -2 .

Force F = ma = 10 × 2.5 = 25 N , in the direction of motion.

Force from the velocity-time graph
Read the slope of the line
velocity goes from 10 to 30 m s⁻¹ in 8 s
↓
Slope = acceleration
a = 30-10 8 = 2.5 m s -2
↓
Apply F = ma
F = 10 kg × 2.5 m s -2
↓
F = 25 N , along the direction of motion
← Back to: 6.5 Newton's Second Law of Motion
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