Answer the following questions with the help of the data given in Table 5.4.
(i) What mass of potassium nitrate would be needed to prepare its saturated solution in 50 g of water at 40 °C?
(ii) A student makes a saturated solution of potassium chloride in water at 80 °C and leaves the solution to cool at room temperature (25 °C). What would she observe as the solution cools? Explain.
(iii) What is the effect of a change in temperature on the solubility of salts? Also, compare the changes in the solubility of the four given salts with increasing temperature from 10 °C to 80 °C.
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(i) At 40 °C, potassium nitrate's solubility is 62 g per 100 g water. For 50 g of water, mass needed = 62 ÷ 2 = 31 g .

(ii) As the potassium chloride solution cools from 80 °C to 25 °C, solubility falls, so the excess salt crystallises out and is seen as solid crystals.

(iii) Solubility generally increases with temperature. The rise is steepest for potassium nitrate (21 → 167), moderate for ammonium chloride and potassium chloride, and very small for sodium chloride (about 36 → 37), which barely changes.

Working from the Table 5.4 data
Part Data used Answer
(i) Potassium nitrate in 50 g of water at 40 °C 62 g per 100 g of water at 40 °C half the water → 62 ÷ 2 = 31 g
(ii) Saturated potassium chloride, 80 °C → 25 °C 54 g at 80 °C, falling to about 35 g near 25 °C solubility drops, so the excess salt crystallises out as solid
(iii) Effect of temperature 10 °C → 80 °C for all four salts solubility generally increases : potassium nitrate rises steeply (21→167), ammonium chloride (24→66) and potassium chloride (35→54) rise moderately, sodium chloride hardly changes (36→37)
← Back to: 5.2.3 Solubility of substances
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