The gravitational attraction on the surface of the Moon (lunar surface) is about 1/6 th of that on the surface of the Earth. An astronaut can throw a ball up to a height of 8 m from the surface of the Earth. How far up will the ball thrown with the same upward velocity travel from the surface of the Moon?

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For the same throwing speed, \(\tfrac{1}{2}mv^2 = mgh \Rightarrow h = \dfrac{v^2}{2g}\), so \(h \propto \dfrac{1}{g}\).

On the Moon \(g\) is \(\tfrac{1}{6}\) of Earth's, so the height is 6 times larger: \(h_{\text{moon}} = 6 \times 8 = 48\ \text{m}\).

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