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The velocity-time graph of an object of mass 10 kg moving along a straight line is shown in Fig. 6.41. Calculate the force acting on the object using the graph.
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From the graph, velocity rises from 10 m s −1 to 30 m s −1 in 8 s (a straight line), so the acceleration is
\( a = \dfrac{30 - 10}{8} = \dfrac{20}{8} = 2.5\ \text{m s}^{-2} \).
Force \( F = ma = 10 \times 2.5 = \mathbf{25\ N} \), in the direction of motion.
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