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Forward force from 95 oarsmen = 95 × 200 = 19000 N.
Backward force from 5 oarsmen = 5 × 200 = 1000 N.
Net force = 19000 − 1000 = 18000 N , in the forward direction.
← Back to concept: 6.2 Balanced and Unbalanced ForcesQuestions at the end of the chapter
Questions at the end of the chapter
Last updated at June 28, 2026 by Teachoo
Forward force from 95 oarsmen = 95 × 200 = 19000 N.
Backward force from 5 oarsmen = 5 × 200 = 1000 N.
Net force = 19000 − 1000 = 18000 N , in the forward direction.
← Back to concept: 6.2 Balanced and Unbalanced Forces