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(i) Using % m/m = \( \dfrac{\text{mass of sugar}}{\text{mass of solution}}\times100 \):
A = \( \dfrac{20}{100}\times100 = 20\% \); B = \( \dfrac{20}{120}\times100 = 16.7\% \); C = \( \dfrac{30}{110}\times100 = 27.3\% \).
(ii) Student C's solution is the most concentrated (27.3%), because it has the most sugar in the least amount of solution.
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