Example 14 (i) - Chapter 10 Class 11 Conic Sections

Last updated at April 16, 2024 by

Example 14 - Find foci, vertices, eccentricity, latus rectum

Example 14 - Chapter 11 Class 11 Conic Sections - Part 2
Example 14 - Chapter 11 Class 11 Conic Sections - Part 3
Example 14 - Chapter 11 Class 11 Conic Sections - Part 4

 

Transcript

Example 14 Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the hyperbolas: (i) x2/9 − y2/16 = 1, The given equation is 𝑥2/9 − 𝑦2/16 = 1 The above equation is of the form 𝑥2/𝑎2 − 𝑦2/𝑏2 = 1 Comparing (1) & (2) a2 = 9 a = 3 & b2 = 16 b = 4 Also, c2 = a2 + b2 c2 = 9 + 16 c2 = 25 c = 5 So, Co-ordinate of foci = (±c, 0) = (±5, 0) Thus, Co-ordinate of foci are (5, 0) & (−5, 0) Vertices = (±a, 0) = (±3, 0) Thus, Vertices are (3, 0) & (−3, 0) Eccentricity e = 𝑐/𝑎 = 𝟓/𝟑 Latus rectum = 2𝑏2/𝑎 = (2 × 16)/3 = 𝟑𝟐/𝟑

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