Question 6 - Figure it out - Page 181 - Chapter 7 Class 7 - Finding the Unknown (Ganita Prakash II)

Transcript

Question 6 Given 4k + 1 = 13, find the values of: (a) 8k + 2 (b) 4k (c) k (d) 4k – 1 (e) – k – 2 Since we eventually need to find the value of k, We do that first Solving 4k + 1 = 13 Taking 1 to right side, it becomes negative 4k = 13 – 1 4k = 12 Taking 4 to right, it becomes division k = 12/4 k = 3 Now, solving our options (a) 8k + 2 Putting k = 3 8k + 2 = 8 × 3 + 2 = 24 + 2 = 26 (b) 4k Putting k = 3 4k = 4 × 3 = 12 (c) k Here, k = 3 (d) 4k – 1 Putting k = 3 4k – 1 = 4 × 3 – 1 = 12 – 1 = 11 (e) – k – 2 Putting k = 3 –k – 2 = –3 – 2 = – (3 + 2) = – 5