Question 2 - Figure it out - Page 181 - Chapter 7 Class 7 - Finding the Unknown (Ganita Prakash II)

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Question 2 Find the value of each unknown: (a) 2y = 60Solving 2y = 60 Taking 2 right side, so it becomes division y = 60/2 y = 30 Question 2 Find the value of each unknown: (b) – 8 = 5x – 3Solving –8 = 5x – 3 Since equation is equal, we take x term on right side 5x – 3 = –8 Taking –3 on right side, it becomes + 3 5x = –8 + 3 5x = – (8 – 3) 5x = – 5 Taking 5 right side, it becomes division x = (−5)/5 x = –1 Question 2 Find the value of each unknown: (c) – 53w = –15Solving –53w = –15 Taking –53 right side, so it becomes division Note: –53 doesn’t become + 53, because it isn’t being added, since –53 is multiplied, it becomes division w = (−15)/(−53) w = 𝟏𝟓/𝟓𝟑 Question 2 Find the value of each unknown: (d) 13 – z = 8Solving 13 – z = 8 Putting 13 on left side, it becomes subtraction –z = 8 – 13 –z = – 13 + 8 –z = – (13 – 8) –z = – 5 We can cancel negative sign on both sides, or write –z = –1 × z –1 × z = –5 z = (−5)/(−1) z = 5 Question 2 Find the value of each unknown: (e) k + 8 = 12 – kSolving k + 8 = 12 – k Taking 8 on left side, it becomes subtraction k = 12 – k – 8 k = (12 – 8) – k k = 4 – k Taking –k from right side to left side, it becomes + k k + k = 4 2k = 4 k = 4/2 k = 2 Question 2 Find the value of each unknown: (f) 7m = m – 3Solving 7m = m – 3 Taking m from right side to left side, it becomes –m 7m – m = –3 6m = –3 Taking 6 to left side, it becomes division m = (−3)/6 m = (−𝟏)/𝟐 Question 2 Find the value of each unknown: (g) 3n = 10 + nSolving 3n = 10 + n Taking n from right side to left side, it becomes –n 3n – n = 10 2n = 10 Taking 2 to left side, it becomes division n = 10/2 n = 5