Ex 10.3, 12 - Chapter 10 Class 11 Conic Sections

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Ex 10.3, 12 - Find ellipse: Vertices (6, 0), foci (4, 0) - Ex 10.3

part 2 - Ex 10.3, 12 - Ex 10.3 - Serial order wise - Chapter 10 Class 11 Conic Sections
part 3 - Ex 10.3, 12 - Ex 10.3 - Serial order wise - Chapter 10 Class 11 Conic Sections

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Transcript

Ex 10.3, 12 Find the equation for the ellipse that satisfies the given conditions: Vertices (ยฑ6, 0), foci (ยฑ4, 0) Given Vertices (ยฑ 6, 0) The vertices are of the form (ยฑa, 0) Hence, the major axis is along x-axis & Equation of ellipse is of the form ๐’™^๐Ÿ/๐’‚^๐Ÿ + ๐’š^๐Ÿ/๐’ƒ^๐Ÿ = 1 From (1) & (2) a = 6 Also given coordinate of foci = (ยฑ4, 0) We know that foci = (ยฑ c, 0) So c = 4 We know that c2 = a2 โˆ’ b2 (4) 2 = (6) 2 โˆ’ b2 b2 = (6) 2 โˆ’ (4) 2 b2 = 36 โˆ’ 16 b2 = 20 Equation of ellipse is ๐‘ฅ^2/๐‘Ž^2 + ๐‘ฆ^2/๐‘^2 = 1 Putting values ๐’™^๐Ÿ/๐Ÿ‘๐Ÿ” + ๐’š^๐Ÿ/๐Ÿ๐ŸŽ = 1

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