Question 11 - Figure it out - Page 44, 45 - Chapter 2 Class 8 - Power Play (Ganita Prakash)
Last updated at Aug. 18, 2025 by Teachoo
Figure it out - Page 44, 45
Question 1
Important
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Class 8 (Ganita Prakash & Old NCERT)
Chapter 2 Class 8 - Power Play (Ganita Prakash)
- Basic Concepts & Formulas
- Introduction
- Exponential Notation and Operations
- Figure it out - Page 22, 23
- The Stones that Shine ...
- Formulas of Exponents
- Magical Pond
- Multiplying & Dividing two numbers with Same Power
- Combinations
- The Other Side of Powers
- Power Lines
- Powers of 10
- Scientific Notation
- Did you ever Wonder..
- Linear Growth vs Exponential Growth
- Getting a sense of Large Numbers
- A Pinch of History
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Figure it out - Page 44, 45
Transcript
Question 11 A digital locker has an alphanumeric (it can have both digits and letters) passcode of length 5. Some example codes are G89P0, 38098, BRJKW, and 003AZ. How many such codes are possible?Our 5-digit passcode looks like Since it is alphanumeric, it can have Digits 0-9, that is 10 digits Letters A-Z, that is 26 alphabets Thus, each position of code has 10 + 26 = 36 options To find the total number of possible passcodes, you multiply the number of options for each position. Total codes = 36 × 36 × 36 × 36 × 36 = 365 = 60,466,176 Thus, there are 365 (or 60,466,176) possible codes.
