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Question 1 (Page 6) - Perfect Squares - and its Patterns - Chapter 1 Class 8 - A Square and a Cube (Ganita Prakash)
Last updated at July 29, 2025 by Teachoo
Class 8 (Ganita Prakash & Old NCERT)
Chapter 1 Class 8 - A Square and a Cube (Ganita Prakash)
- Introduction
- Square Numbers
- Perfect Squares - and its Properties
-
Perfect Squares - and its Patterns
- Square Root
- Smallest number multiply or divide to get perfect square
- Estimating Square Root
- Figure it out - Page 10, 11
- Cubic Numbers
- Perfect Cubes - and its Properties
- Perfect Cubes - and its Patterns
- Cube Root
- Smallest number multiply or divide to get perfect cube
- A pinch of History
- Figure it out - Page 16, 17
Transcript
Question 1 (Page 6) Using the pattern, find 362, given that 352 = 1225. To find 362, we must add the 36th consecutive odd number to 352. Finding 36th odd number The 1st odd number is 1, 2nd odd number is 3, 3rd number is 5, …, 6th odd number is 11 and so on. Thus, nth odd number would be 2n – 1 And, 36th odd number is 2(36) − 1 = 72 − 1 = 71 Calculating 362 362 = 352 + 71 = 1225 + 71 = 1296
