Ā
Division
Last updated at August 5, 2026 by Teachoo
Ā
Transcript
Ex5.1, 11 Find the multiplicative inverse of the Complex number 4 ā 3š Multiplicative inverse of z = z ā 1 Multiplicative inverse of z = 1/š§ Putting z = 4 ā 3i multiplicative inverse of 4 ā 3i = 1/(4 ā3 š) Rationalizing = 1/(4 ā3š) Ć(4 + 3š)/(4 + 3š) = (4+3i)/(4 ā3i)(4 + 3š) Using (a ā b ) ( a + b ) = a 2 ā b 2 = (4 + 3š)/((4)2ā(3š)2) = (4 + 3i)/(16 ā 9š2) Putting i 2 = ā 1 = (4 + 3š)/(16 ā9 (ā1) ) = (4 + 3š)/(16 + 9) = (4 + 3š)/25 = 4/25+3/25 š