Last updated at May 29, 2018 by Teachoo

Transcript

Ex 3.4, 4 Find the principal and general solution of cosec x = 2 Given cosec x = 2 1/sin = -2 sin x = ( 1)/2 We know that sin 30 = 1/2 But we need negative value of sin x sin x is negative in lllrd & lVth Quadrant Value in IIIrd Quadrant = 180 + 30 = 210 Value in IVth Quadrant = 360 30 = 330 So, Principle Solution are x = 210 and x = 330 x = 210 /180 and x = 330 /180 x = 7 /6 and x = 11 /6 To find general solution Let sin x = sin y sin x = 1/2 From (1) and (2) sin y = 1/2 sin y = sin 7 /6 y = 7 /6 Since sin x = sin y General Solution is x = n + ( -1)n y where n Z Put y = 7 /6 Hence, x = n +(-1)n 7 /6 Where n Z

Ex 3.1, 1
Important

Ex 3.1, 2 Important

Ex 3.2, 7 Important

Ex 3.2, 8 Important

Ex 3.2, 9 Important

Ex 3.3, 4 Important

Ex 3.3, 5 Important

Ex 3.3, 8 Important

Ex 3.3, 11 Important

Ex 3.3, 18 Important

Ex 3.3, 23 Important

Ex 3.3, 21 Important

Example 24 Important

Ex 3.4, 4 Important You are here

Ex 3.4, 8 Important

Ex 3.4, 9 Important

Example 27 Important

Example 28 Important

Misc 4 Important

Misc 7 Important

Class 11

Important Question for exams Class 11

- Chapter 1 Class 11 Sets
- Chapter 2 Class 11 Relations and Functions
- Chapter 3 Class 11 Trigonometric Functions
- Chapter 4 Class 11 Mathematical Induction
- Chapter 5 Class 11 Complex Numbers
- Chapter 6 Class 11 Linear Inequalities
- Chapter 7 Class 11 Permutations and Combinations
- Chapter 8 Class 11 Binomial Theorem
- Chapter 9 Class 11 Sequences and Series
- Chapter 10 Class 11 Straight Lines
- Chapter 11 Class 11 Conic Sections
- Chapter 12 Class 11 Introduction to Three Dimensional Geometry
- Chapter 13 Class 11 Limits and Derivatives
- Chapter 14 Class 11 Mathematical Reasoning
- Chapter 15 Class 11 Statistics
- Chapter 16 Class 11 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.