Last updated at March 8, 2017 by Teachoo

Transcript

Ex 2.2,1 Let A = {1, 2, 3, … , 14}. Define a relation R from A to A by R = {(x, y): 3x – y = 0, where x, y ∈ A}. Write down its domain, codomain and range. It is given that 3x – y = 0 ⇒ 3x = 0 + y ⇒ 3x = y ⇒ y = 3x R = {(1, 3), (2, 6), (3, 9), (4, 12)} Domain of R = Set of all first elements of the ordered pairs in the relation. = {1, 2, 3, 4} Range of R = Set of all second elements of the ordered pairs in the relation. = {3, 6, 9, 12} Codomain R is defined from A to A ∴ Codomain of R = A = {1, 2, 3, …, 14}

Finding Relation - Set-builder form given

Chapter 2 Class 11 Relations and Functions

Concept wise

- Finding Cartesian Product
- Equality of 2 ordered pairs
- Number of elements
- Operations on sets+ cartesian product
- Relations - Definition
- Finding Relation - Set-builder form given
- Finding Relation - Arrow Depiction given
- Number of Relations
- Functions - Definition
- Finding values at certain points
- Different Functions and their graphs
- Finding Domain and Range - By drawing graphs
- Finding Domain and Range - General Method
- Algebra of real functions

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.