Ex 2.1

Chapter 2 Class 11 Relations and Functions
Serial order wise

Transcript

Ex 2.1, 10 The Cartesian product A × A has 9 elements among which are found (–1, 0) and (0, 1). Find the set A and the remaining elements of A × A. Since A × A has 9 elements So, A would have 3 elements Let A = {a, b, c} Now, A × A = {a, b, c} × {a, b, c} = { (a, a) , (a, b) , (a, c), (b, a) , (b, b) , (b, c), (c, a) , (c, b) , (c, c)} (As 3 × 3 = 9) Now, (–1,0) is in set A × A And, (0, 1) is in set A × A Thus, a = –1 , b = 0, c = 1 So, A = { a, b, c} = {– 1, 0, 1}. Now A × A = {– 1, 0, 1} × {– 1, 0, 1} A × A = {(–1, –1), (– 1, 1), (–1, 0) (0, – 1), (0, 0), (0, 1), (1, – 1), (1, 0),(1, 1)} (Taking a = –1, b = 0) (Taking b = 0, c = 1) Thus, remaining elements of set A × A are (– 1, – 1), (– 1, 1), (0, – 1), (0, 0), (1, – 1), (1, 0), and (1, 1)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.