Question 26 - Teachoo Sample Paper - Computer Science Class 12 - Solutions to CBSE Sample Paper - Computer Science Class 12

Predict the output of the Python code given below:

Text1="XYZ-456"

Text2=""

I=len(Text1)-1

while I>=0:

    if Text1[I]>="0" and Text1[I]<="9" :

        Val=int(Text1[I])

        Val=Val*2

        Text2=Text2+str(Val)

    elif Text1[I]>="A" and Text1[I]<="Z" :

        Text2= Text2+(Text1[I-1])

    else:

        Text2=Text2+"*"

    I-=1

print (Text2)

Answer:

Answer by student

The output of the Python code is 12108*YX6 .

Detailed answer by teachoo

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• The code first defines two strings, Text1 and Text2 . The string Text1 contains the characters "XYZ-456". The string Text2 is initially empty.

• The code then defines a variable I and initializes it to the length of the string Text1 minus 1 . This means that I will initially be equal to 5, since the length of the string Text1 is 6.

• The code then enters a while loop. The loop will iterate as long as I is greater than or equal to 0.

• Inside the loop, the code first checks if the character at index I of the string Text1 is a digit . If it is, then the code converts the character to an integer, multiplies it by 2, and appends the resulting integer to the string Text2.

• Otherwise, if the character at index I of the string Text1 is a letter, then the code appends the character at index I - 1 of the string Text1 to the string Text2.

• Finally, the code decrements I by 1 and repeats the loop.

• The loop will terminate when I is equal to -1. At this point, the string Text2 will contain the characters " 12108*YX6 ".

• The code then prints the string Text2.

So, the correct output of the code is 12108*YX6.

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