Last updated at Dec. 23, 2019 by Teachoo

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Ex 1.4, 9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (i) A – B A – B = A – (A ∩ B) A ∩ B = {3, 6, 9, 12, 15, 18, 21} ∩ {4, 8, 12, 16, 20} = { 12} A – B = A – (A ∩ B) = {3, 6, 9, 12, 15, 18, 21} – { 12} = {3, 6, 9, 15, 18, 21} Ex 1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (ii) A – C A – C = A – (A ∩ C) A ∩ C = {3, 6, 9, 12, 15, 18, 21} ∩ {2, 4, 6, 8, 10, 12, 14, 16} = {6, 12} A – C = A – (A ∩ C) = {3, 6, 9, 12, 15, 18, 21} – { 6, 12} = {3, 9, 15, 18, 21} Ex1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (iii) A – D A – D = A – (A ∩ D) A ∩ D = {3, 6, 9, 12, 15, 18, 21} ∩ {5, 10, 15, 20} = {15} A – D = A – (A ∩ D) = {3, 6, 9, 12, 15, 18, 21} – { 15} = {3, 6, 9, 12, 18, 21} Ex1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (iv) B – A B – A = B – (B ∩ A) B ∩ A = {4, 8, 12, 16, 20} ∩ {3, 6, 9, 12, 15, 18, 21} = {12} B – A = B – (B ∩ A) = {4, 8, 12, 16, 20} – {12} = {4, 8, 16, 20} Ex1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (v) C – A C – A = C – (C ∩ A) C ∩ A = {2, 4, 6, 8, 10, 12, 14, 16} ∩ {3, 6, 9, 12, 15, 18, 21} = {6,12} C – A = C – (C ∩ A) = {2, 4, 6, 8, 10, 12, 14, 16} – {6,12} = {2, 4, 8, 10, 14, 16} Ex 1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (vi) D – A D – A = D – (D ∩ A) D ∩ A = {5, 10, 15, 20} ∩ {3, 6, 9, 12, 15, 18, 21} = {15} D – A = D – (D ∩ A) = {5, 10, 15, 20} – {15} = {5, 10, 20} Ex 1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (vii) B – C B – C = B – (B ∩ C) B ∩ C = {4, 8, 12, 16, 20} ∩ {2, 4, 6, 8, 10, 12, 14, 16} = {4,8,12,16} B – C = B – (B ∩ C) = {4, 8, 12, 16, 20} – {4,8,12,16} = {20} Ex1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (viii) B – D B – D = B – (B ∩ D) B ∩ D = {4, 8, 12, 16, 20} ∩ {5, 10, 15, 20} = {20} B – D = B – (B ∩ D) = {4, 8, 12, 16, 20} – {20} = {4, 8, 12, 16} Ex 1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (ix) C – B C – B = C – (C ∩ B) C ∩ B = {2, 4, 6, 8, 10, 12, 14, 16} ∩ {4, 8, 12, 16, 20} = {4,8,12,16} C – B = C – (C ∩ B) = {2, 4, 6, 8, 10, 12, 14, 16} – {4,8,12,16} = {2, 6, 10, 14} Ex1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (x) D – B D – B = D – (D ∩ B) D ∩ B = {5, 10, 15, 20} ∩ {4, 8, 12, 16, 20} = {20} D – B = D – (D ∩ B) = {5, 10, 15, 20} – {20} = {5, 10, 15} Ex1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (xi) C – D C – D = C – (C ∩ D) C ∩ D = {2, 4, 6, 8, 10, 12, 14, 16} ∩ {5, 10, 15, 20} = {10} C – D = C – (C ∩ D) = {2, 4, 6, 8, 10, 12, 14, 16} – {10} = {2, 4, 6, 8, 12, 14, 16} Ex1.4,9 If A = {3, 6, 9, 12, 15, 18, 21}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12, 14, 16}, D = {5, 10, 15, 20}; find (xii) D – C D – C = D – (D ∩ C) D ∩ C = {5, 10, 15, 20} ∩ {2, 4, 6, 8, 10, 12, 14, 16} = {10} D – C = D – (D ∩ C) = {5, 10, 15, 20} – {10} = {5, 15, 20}

Chapter 1 Class 11 Sets

Concept wise

- Depiction and Defination
- Depicition of sets - Roster form
- Depicition of sets - Set builder form
- Intervals
- Null Set
- Finite/Infinite
- Equal sets
- Subset
- Power Set
- Universal Set
- Venn Diagram and Union of Set
- Intersection of Sets
- Difference of sets
- Complement of set
- Number of elements in set - 2 sets (Direct)
- Number of elements in set - 2 sets - (Using properties)
- Number of elements in set - 3 sets
- Proof - Using properties of sets
- Proof - where properties of sets cant be applied,using element

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.