Example 3
Suppose we throw a die once.
What is the probability of getting a number greater than 4 ?
Total outcomes that can occur are 1, 2, 3, 4, 5, 6
Total number of outcomes = 6
Numbers greater than 4 = 5 & 6
Number of outcomes where number is greater than 4 = 2
Probability of getting a number greater than 4
= (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠 𝑤ℎ𝑒𝑟𝑒 𝑡ℎ𝑒𝑟𝑒 𝑖𝑠 𝑎 𝑛𝑢𝑚𝑏𝑒𝑟 𝑔𝑟𝑒𝑎𝑡𝑒𝑟 𝑡ℎ𝑎𝑛 4)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠)
= 2/6
= 1/3
Example 3 (Method 1)
Suppose we throw a die once.
(ii) What is the probability of getting a number less than or equal to 4 ?
Total outcomes that can occur are 1, 2, 3, 4, 5, 6
Total number of outcomes = 6
Numbers less than or equal to 4 = 1, 2, 3, & 4
Number of outcomes where number is less than or equal to 4 = 4
Probability of getting a number less than or equal to 4
= (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠 𝑤ℎ𝑒𝑟𝑒 𝑡ℎ𝑒𝑟𝑒 𝑖𝑠 𝑎 𝑛𝑢𝑚𝑏𝑒𝑟 𝑙𝑒𝑠𝑠 𝑡ℎ𝑎𝑛 𝑜𝑟 𝑒𝑞𝑢𝑎𝑙 𝑡𝑜 4)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠)
= 4/6
= 2/3
Example 3 (Method 2)
Suppose we throw a die once.
(ii) What is the probability of getting a number less than or equal to 4 ?
P(getting a number less than or equal to 4)
= 1 – P(not getting a number less than or equal to 4)
= 1 – P(getting a number greater than 4)
= 1 – 1/3
= 2/3

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

Hi, it looks like you're using AdBlock :(

Displaying ads are our only source of revenue. To help Teachoo create more content, and view the ad-free version of Teachooo... please purchase Teachoo Black subscription.

Please login to view more pages. It's free :)

Teachoo gives you a better experience when you're logged in. Please login :)

Solve all your doubts with Teachoo Black!

Teachoo answers all your questions if you are a Black user!