Last updated at Dec. 8, 2016 by Teachoo

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Example 3 Suppose we throw a die once. What is the probability of getting a number greater than 4 ? Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Total number of outcomes = 6 Numbers greater than 4 = 5 & 6 Number of outcomes where number is greater than 4 = 2 Probability of getting a number greater than 4 = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ๐คโ๐๐๐ ๐กโ๐๐๐ ๐๐ ๐ ๐๐ข๐๐๐๐ ๐๐๐๐๐ก๐๐ ๐กโ๐๐ 4)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 2/6 = 1/3 Example 3 (Method 1) Suppose we throw a die once. (ii) What is the probability of getting a number less than or equal to 4 ? Total outcomes that can occur are 1, 2, 3, 4, 5, 6 Total number of outcomes = 6 Numbers less than or equal to 4 = 1, 2, 3, & 4 Number of outcomes where number is less than or equal to 4 = 4 Probability of getting a number less than or equal to 4 = (๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ๐คโ๐๐๐ ๐กโ๐๐๐ ๐๐ ๐ ๐๐ข๐๐๐๐ ๐๐๐ ๐ ๐กโ๐๐ ๐๐ ๐๐๐ข๐๐ ๐ก๐ 4)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐ข๐ก๐๐๐๐๐ ) = 4/6 = 2/3 Example 3 (Method 2) Suppose we throw a die once. (ii) What is the probability of getting a number less than or equal to 4 ? P(getting a number less than or equal to 4) = 1 โ P(not getting a number less than or equal to 4) = 1 โ P(getting a number greater than 4) = 1 โ 1/3 = 2/3

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.