Ex 12.1, 9 - Chapter 12 Class 10 Surface Areas and Volumes

Last updated at August 2, 2026 by

Ex 12.1, 9 - A wooden article was made by scooping out a - Ex 12.1

part 2 - Ex 12.1, 9 - Ex 12.1 - Serial order wise - Chapter 12 Class 10 Surface Areas and Volumes
part 3 - Ex 12.1, 9 - Ex 12.1 - Serial order wise - Chapter 12 Class 10 Surface Areas and Volumes

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Ex 12.1, 9 A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in figure. If the height of the cylinder is 10 cm, and its base is of radius 3.5 cm, find the total surface area of the article. Now, Total surface area of article = Curved surface area of cylinder + 2 × Curved surface area of hemisphere Curved surface area of cylinder Radius = r = 3.5 cm Height of the cylinder = h = 10 cm Curved surface area of cylinder = 2πrh = 2 ×22/7 × 3.5 × 10 = 2 × 22/7× 35 = 2 × 22 × 5 = 220 cm2 Surface area of hemisphere Radius of hemisphere = r = 3.5 cm Surface area of hemisphere = 2πr2 = 2 × 𝟐𝟐/𝟕 × (𝟑.𝟓)^𝟐 = 2 × 22/7 × 3.5 × 3.5 = 2 × 22 × 0.5 × 3.5 = 44 × 0.5 × 3.5 = 77 cm2 Thus, Surface area of 2 hemisphere = 2 ×"Surface area of hemisphere" = 2 ×77 = 154 cm2 Therefore, Total surface area of article = Curved surface area of cylinder + 2 × Curved surface area of hemisphere = 220 + 154 = 374 cm2

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