Question 1 - Frustum of a cone - Volume - Chapter 12 Class 10 Surface Areas and Volumes

Last updated at August 2, 2026 by

Ex 13.4, 1 - A drinking glass is in shape of a frustum - Frustum of a cone - Volume

Ex 13.4, 1 - Chapter 13 Class 10 Surface Areas and Volumes - Part 2

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Question 1 A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass. Since glass is in from of frustum Capacity of glass = Volume of frustum = 1/3 šœ‹ā„Ž(š‘Ÿ12+š‘Ÿ22+š‘Ÿ1š‘Ÿ2) Hence , h = height of frustum = 14 cm r1 = (š·š‘–š‘Žš‘šš‘’š‘”š‘’š‘Ÿ š‘œš‘“ 1^š‘ š‘” š‘’š‘›š‘‘)/2 = 4/2 = 2 cm r2 = (š·š‘–š‘Žš‘šš‘’š‘”š‘’š‘Ÿ š‘œš‘“ 2^š‘›š‘‘ š‘’š‘›š‘‘)/2 = 2/2 = 1 cm Volume of glass = 1/3 šœ‹ā„Ž(š‘Ÿ12+š‘Ÿ22+š‘Ÿ1š‘Ÿ2) = 1/3Ɨ22/7Ɨ14(22+12+2Ɨ1) = 1/3 Ɨ 22Ɨ2(4+1+2) = (22 Ɨ 2 Ɨ 7)/3 = 308/3 = 102.66 cm3 Hence, volume of glass = 102.66 cm3

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