Ex 12.1, 4 - The wheels of a car are of diameter 80 cm each - Ex 12.1

Ex 12.1, 4 - Chapter 12 Class 10 Areas related to Circles - Part 2
Ex 12.1, 4 - Chapter 12 Class 10 Areas related to Circles - Part 3

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Question 4 The wheels of a car are of diameter 80 cm each. How many complete revolutions does each wheel make in 10 minutes when the car is travelling at a speed of 66 km per hour? Number of revolutions = (š‘‡š‘œš‘”š‘Žš‘™ š‘‘š‘–š‘ š‘”š‘Žš‘›š‘š‘’)/(š·š‘–š‘ š‘”š‘Žš‘›š‘š‘’ š‘š‘œš‘£š‘’š‘Ÿš‘’š‘‘ š‘–š‘› 1 š‘Ÿš‘’š‘£š‘œš‘™š‘¢š‘”š‘–š‘œš‘›) Diameter of circle = 80 cm radius = r = 80/2 = 40 cm Distance covered in one revolution = Circumference of wheel = 2 šœ‹r = 2 Ć—šœ‹Ć—40 = 80Ļ€ cm Now, we find total distance covered We know that, Speed = š·š‘–š‘ š‘”š‘Žš‘›š‘š‘’/(š‘‡š‘–š‘šš‘’ ) Here, Speed = 66 km/hr Time = 10 minutes = 10/60 hour = 1/6 hour Putting value in formula 66 = Distance/(1/6) 66 Ɨ1/6 = Distance 11 = Distance Distance = 11 km Distance = 11 km = 11 Ɨ 1000 m = 11000 m = 11000 Ɨ100 cm = 1100000 cm Now , Number of revolutions = (š‘‡š‘œš‘”š‘Žš‘™ š‘‘š‘–š‘ š‘”š‘Žš‘›š‘š‘’)/(š·š‘–š‘ š‘”š‘Žš‘›š‘š‘’ š‘š‘œš‘£š‘’š‘Ÿš‘’š‘‘ š‘–š‘› 1 š‘Ÿš‘’š‘£š‘œš‘™š‘¢š‘”š‘–š‘œš‘›) = 1100000/80Ļ€ = 110000/8Ļ€ = 110000/(8 Ɨ 22/7) = (110000 Ɨ 7)/(8 Ɨ 22) = 4375 Hence, number of revolutions = 4375

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