Question 5 - MCQs from (Past Year Papers & NCERT Exemplar) - Chapter 12 Class 10 - Electricity
Last updated at April 16, 2024 by Teachoo
A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be where, e = 1.6 × 10
–19
C
(a) 10
20
(b) 10
16
(c) 10
18
(d) 10
23
Answer:
Given,
I
= 1 A
t = 16 seconds
e =
1.6 × 10
-19
C
We know that,
I = Q / t —------(i)
Where,
Q is the electric charge
t is time
We know that,
Q
= n*e —---------(ii)
Where,
n
is the number of electrons.
e
is the charge of one electron.
Substituting (ii) in (i),
I = n*e / t
1 = n *
1.6 × 10
-19
/ 16
n
= 1 * 16 /
1.6 × 10
-19
n
= 10 * 10
19
Therefore,
n = 10
20
So, the
correct answer is (a).
Transcript
Question 5 A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be where, e = 1.6 × 10–19 C (a) 1020 (b) 1016 (c) 1018 (d) 1023Given,
I = 1 A
t = 16 seconds
e = 1.6 × 10-19 C
We know that,
I = 𝑄/𝑡
Where,
Q is the electric charge
t is time
We know that,
Q = n*e
Where,
n is the number of electrons.
e is the charge of one electron.
Substituting (ii) in (i),
I = n × 𝑒/𝑡
1 = n × (1.6 × 10 − 19)/16
n = 1 × 16/(1.6 × 10 − 19)
n = 10 × 1019
Therefore, n = 1020
So, the correct answer is (a)
CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo
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