Question 5 If a, are the zeros of the quadratic polynomial π(π₯)=π₯^2β(π+6) π₯+2 (2πβ1), then the value of π, if πΌ+π½=1/2 πΌπ½ is (a) β7 (b) 7 (c) β3 (d) 3
Given
πΌ+π½=1/2 πΌπ½
Sum of Zeroes = π/π Γ Product of Zeroes
(βπ)/π=1/2 Γπ/π
(β(β(π + 6))/1=1/2 Γ(2(2πβ1))/1
(π+π)=ππβπ
6+1=2πβπ
7=π
π=π
So, the correct answer is (b)

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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