Question 5 If a, are the zeros of the quadratic polynomial π(π₯)=π₯^2β(π+6) π₯+2 (2πβ1), then the value of π, if πΌ+π½=1/2 πΌπ½ is (a) β7 (b) 7 (c) β3 (d) 3
Given
πΌ+π½=1/2 πΌπ½
Sum of Zeroes = π/π Γ Product of Zeroes
(βπ)/π=1/2 Γπ/π
(β(β(π + 6))/1=1/2 Γ(2(2πβ1))/1
(π+π)=ππβπ
6+1=2πβπ
7=π
π=π
So, the correct answer is (b)

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.