Example 7 - Divide 3x3 + x2 + 2x + 5 by 1 + 2x + x2 - Examples

  1. Chapter 2 Class 10 Polynomials
  2. Serial order wise

Transcript

Example 7 Divide 3x3 + x2 + 2x + 5 by 1 + 2x + x2. We follow these steps 1. Since we have 3x3, we multiply by 3x 2. Thus, the remainder will be difference of 3x3 + x2 + 2x and 3x3 + 6x2 + 3x 3. Which comes out to be -5x2 - x 4. Now, we have -5x2, so we multiply with -5 5. So, the remainder will be difference of -5x2 - x + 5 and -5x2 -10x - 5 6. Which comes out to be 9x + 10 Therefore, Quotient = 3x – 5 Remainder = 9x + 10

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.