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Example 7 - Chapter 2 Class 10 Polynomials (Term 1)

Last updated at July 12, 2018 by

Example 7 - Divide 3x3 + x2 + 2x + 5 by 1 + 2x + x2 - Examples

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Example 7 Divide 3x3 + x2 + 2x + 5 by 1 + 2x + x2. We follow these steps 1. Since we have 3x3, we multiply by 3x 2. Thus, the remainder will be difference of 3x3 + x2 + 2x and 3x3 + 6x2 + 3x 3. Which comes out to be -5x2 - x 4. Now, we have -5x2, so we multiply with -5 5. So, the remainder will be difference of -5x2 - x + 5 and -5x2 -10x - 5 6. Which comes out to be 9x + 10 Therefore, Quotient = 3x – 5 Remainder = 9x + 10

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.