Ex 2.2, 3 - Chapter 2 Class 6 Whole Numbers - Part 4

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  1. Chapter 2 Class 6 Whole Numbers
  2. Serial order wise

Transcript

Ex 2.2, 3 Find the value of the following: (d) 3845 × 5 × 782 + 769 × 25 × 218 3845 × 5 × 782 + 769 × 25 × 218 There is no value common We try to find common by writing 25 as 5 × 5 = 3845 x 5 × 782 + 769 × 5 × 5 × 218 = 3845 × 5 × 782 + 3845 × 5 × 218 = (3845 × 5) × 782 + (3845 × 5) × 218 = 19225 × 782 + 19225 × 218 = 19225 × (782 + 218) = 19225 × 1000 = 19225000

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.