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Ex 2.3, 4 - On dividing x3 - 3x2 + x + 2 by polynomial g(x) - Ex 2.3

Ex 2.3, 4 - Chapter 2 Class 10 Polynomials - Part 2
Ex 2.3, 4 - Chapter 2 Class 10 Polynomials - Part 3

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Ex2.3, 4 On dividing x3 3x2 + x + 2 by a polynomial g(x), the quotient and remainder were x 2 and 2x + 4, respectively. Find g(x). Introduction Dividend = Divisor Quotient + Remainder 7 = 3 2 + 1 Ex2.3, 4 On dividing x3 3x2 + x + 2 by a polynomial g(x), the quotient and remainder were x 2 and 2x + 4, respectively. Find g(x). We know that Dividend = Divisor Quotient + Remainder Here, Dividend = x3 3x2 + x + 2 Divisor = g(x) Quotient = (x 2) Remainder = ( 2x + 4) Putting values in (1) x3 3x2 + x + 2 = g(x) (x 2) + (-2x + 4) x3 3x2 + x + 2 + 2x 4 = g(x) (x 2) x3 3x2 + 3x 2 = g(x) (x 2) g(x) = ( 3 3 2 + 3 2)/( 2) Therefore, g(x) = Quotient = x2 x + 1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.