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Last updated at May 29, 2018 by Teachoo

Transcript

Ex2.3, 4 On dividing x3 3x2 + x + 2 by a polynomial g(x), the quotient and remainder were x 2 and 2x + 4, respectively. Find g(x). Introduction Dividend = Divisor Quotient + Remainder 7 = 3 2 + 1 Ex2.3, 4 On dividing x3 3x2 + x + 2 by a polynomial g(x), the quotient and remainder were x 2 and 2x + 4, respectively. Find g(x). We know that Dividend = Divisor Quotient + Remainder Here, Dividend = x3 3x2 + x + 2 Divisor = g(x) Quotient = (x 2) Remainder = ( 2x + 4) Putting values in (1) x3 3x2 + x + 2 = g(x) (x 2) + (-2x + 4) x3 3x2 + x + 2 + 2x 4 = g(x) (x 2) x3 3x2 + 3x 2 = g(x) (x 2) g(x) = ( 3 3 2 + 3 2)/( 2) Therefore, g(x) = Quotient = x2 x + 1

Ex 2.3

Ex 2.3, 1 (i)
Deleted for CBSE Board 2022 Exams

Ex 2.3, 1 (ii) Important Deleted for CBSE Board 2022 Exams

Ex 2.3, 1 (iii) Deleted for CBSE Board 2022 Exams

Ex 2.3, 2 (i) Deleted for CBSE Board 2022 Exams

Ex 2.3, 2 (ii) Important Deleted for CBSE Board 2022 Exams

Ex 2.3, 2 (iii) Deleted for CBSE Board 2022 Exams

Ex 2.3, 3 Important Deleted for CBSE Board 2022 Exams

Ex 2.3, 4 Important Deleted for CBSE Board 2022 Exams You are here

Ex 2.3, 5 Deleted for CBSE Board 2022 Exams

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.