Example 2
Two coins are tossed simultaneously 500 times, and we get
Two heads : 105 times
One head : 275 times
No head : 120 times
Find the probability of occurrence of each of these events.
Let E1 be event of two heads coming
E2 be event of one heads coming
E3 be event of no heads coming
P(two heads) = P(E1) = 105/500 = 0.21
P(one head) = P(E2) = 275/500 = 0.55
P(no head) = P(E3) = 120/500 = 0.24

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.