Get live Maths 1-on-1 Classs - Class 6 to 12

Miscellaneous

Misc 1 (i)
Deleted for CBSE Board 2023 Exams

Misc 1 (ii) Deleted for CBSE Board 2023 Exams

Misc 1 (iii) Deleted for CBSE Board 2023 Exams

Misc 1 (iv) Deleted for CBSE Board 2023 Exams

Misc 2 (i) Important Deleted for CBSE Board 2023 Exams

Misc 2 (ii) Deleted for CBSE Board 2023 Exams

Misc 2 (iii) Deleted for CBSE Board 2023 Exams

Misc 3 Important Deleted for CBSE Board 2023 Exams

Misc 4 (i) Deleted for CBSE Board 2023 Exams

Misc 4 (ii) Important Deleted for CBSE Board 2023 Exams

Misc 4 (iii) Deleted for CBSE Board 2023 Exams

Misc 5 Important Deleted for CBSE Board 2023 Exams

Misc 6 (i) Important Deleted for CBSE Board 2023 Exams

Misc 6 (ii) Deleted for CBSE Board 2023 Exams You are here

Misc 7 Important Deleted for CBSE Board 2023 Exams

Last updated at March 16, 2023 by Teachoo

Misc, 6 Check the validity of the statements given below by the method given against it. (ii) q: If n is a real number with n > 3, then n2 > 9 (by contradiction method). q : if n is real number with n > 3 then n 3 > 9 Let the component statement is given in the form if p then q By contradiction method By assuming if p then q & we get a contradiction that our assumption is Wrong It p then q let n > 3 & n2 9 Put n = + 1 + a. Squaring both side. (n)2 = (3 + a)2 (n)2 = (3)2 + (a)2 + 2 3 a (n)2 = 9 + a2 + 6a (n)2 =9 + a (6 + 9) (n)2 > 9 hence n2 > 9 We get a contradictive because we assume n2 9 Hence the given statement is live .