
Introducing your new favourite teacher - Teachoo Black, at only βΉ83 per month
Last updated at Jan. 31, 2022 by Teachoo
Ex 4.2, 3 Check which of the following are solutions of the equation π₯β2π¦=4 and which are not: (iii) (4, 0) Given equation π₯β2π¦=4 Putting x = 4 and y = 0 in LHS πβππ =4β2(0) =π Since, LHS = RHS Hence, (4, 0) is a solution