Question 3 - Case Based Questions (MCQ) - Chapter 12 Class 12 Linear Programming
Last updated at July 27, 2026 by Teachoo
A manufacturer manufactures two types of tea-cups, A and B. Three machines are needed for manufacturing the tea cups. The time in minutes required for manufacturing each cup on the machines is given below:
Each machine is available for a maximum of six hours per day. If the profit on each cup of type A is Rs. 1.50 and that on each cup of type B is Rs. 1.00. Then answer the following questions:
Question A manufacturer manufactures two types of tea-cups, A and B. Three machines are needed for manufacturing the tea cups. The time in minutes required for manufacturing each cup on the machines is given below: Each machine is available for a maximum of six hours per day. If the profit on each cup of type A is Rs. 1.50 and that on each cup of type B is Rs. 1.00. Then answer the following questions:
Let Number of cups of Type A = x
Number of cups of Type B = y
Machine I
Time required on
Type A → 12 Min
Type B → 6 Min
Max Available Time
= 360 min
∴ 12x + 6y ≤ 360
2x + y ≤ 60
Machine II
Time required on
Type A → 18 Min
Type B → 0 Min
Max Available Time
= 360 min
∴ 18x + 0.y ≤ 360
x ≤ 20
Machine III
Time required on
Type A → 6 Min
Type B → 9 Min
Max Available Time
= 360 min
∴ 6x + 9y ≤ 360
2x + 3y ≤ 120
As we need to maximize the Profit
Given that the profit on each cup of type A is Rs. 1.50 and that on each cup of type B is Rs. 1.00
∴ Z = 1.50 x + 1.00 y
Combining all constraints :
Max Z = 1.5x + y
Subject to constraints,
2x + y ≤ 60,
2x + 3y ≤ 120,
x ≤ 20,
& x ≥ 0 , y ≥ 0
Question 1 Let x be the number of A type tea cups and y be the number of B type tea cups. Then the objective function associative with the given problem is: (a) Max. Z = 1.50 x + y (b) Max. Z = x + 1.50 y (c) Min. Z = 1.50 x – y (d) Min. Z = x – 1.50 y.
Here, we need to
Maximize Z = 1.5x + y
So, the correct answer is (a)
Question 2 Let x be the number of A type tea cups and y be the number of B type tea cups. Then the constraints associative with the given problem are: (A) ■8(2𝑥+𝑦≥60@𝑥≤20@2𝑥+3𝑦≤120) (B) ■8(2𝑥+𝑦≤60@𝑥≤20@2𝑥+3𝑦≤120) (C) ■8(2𝑥+𝑦≤60@𝑥≥20@2𝑥+3𝑦≤120) (D) ■8(2𝑥+𝑦≤60@𝑥=20@2𝑥+3𝑦≥120)
Constraints in our LPP are
2x + y ≤ 60,
2x + 3y ≤ 120,
x ≤ 20,
So, the correct answer is (b)
Question 3 The non-negative conditions are given as: (a) x ⤶7≥ 0, y ⤶7≥ 0 (b) x ⤶7≥ 0, y ≤ 0 (c) x ≤ 0, y ⤶7≥ 0 (d) x ≤ 0, y ≤ 0
Non-negative conditions are where x, y cannot be negative
Therefore, they are x ⤶7≥ 0, y ⤶7≥ 0
So, the correct answer is (a)
Question 4 Feasible region has how many corner points? (a) 3 (b) 4 (c) 5 (d) 6
Our LPP is
Max Z = 1.5x + y
Subject to constraints,
2x + y ≤ 60,
2x + 3y ≤ 120,
x ≤ 20,
& x ≥ 0 , y ≥ 0
Since feasible region as 5 corner points – A, B, C, D, O
So, the correct answer is (c)
Question 5 The Maximum Profit is : (a) Rs. 40 (b) Rs. 50 (c) Rs. 30 (d) Rs 52.5
Finding values at corner points
Hence,
Maximum Profit = Rs. 52.50
So, the correct answer is (d)
Made by
Davneet Singh
Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.
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