A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.



Given mass of the compound = 0.24g

Mass of Boron in the given sample = 0.096g

Mass of Oxygen in the given sample = 0.144g


Percentage composition = (Mass of one element / Mass of given sample) x 100


Percentage of Boron = (Mass of one Boron / Mass of given sample) x 100

                                           = (0.096 / 0.24) x 100

                                           = 40%


Percentage of Oxygen = (Mass of one Oxygen / Mass of given sample) x 100

                                             = (0.144 / 0.24) x 100

                                             = 60%


Hence percentage composition of the sample is 40% Boron and 60% Oxygen

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CA Maninder Singh is a Chartered Accountant for the past 13 years and a teacher from the past 17 years. He teaches Science, Economics, Accounting and English at Teachoo