A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Answer
Given mass of the compound = 0.24g
Mass of Boron in the given sample = 0.096g
Mass of Oxygen in the given sample = 0.144g
Percentage composition = (Mass of one element / Mass of given sample) x 100
Percentage of Boron = (Mass of one Boron / Mass of given sample) x 100
= (0.096 / 0.24) x 100
= 40%
Percentage of Oxygen = (Mass of one Oxygen / Mass of given sample) x 100
= (0.144 / 0.24) x 100
= 60%
Hence percentage composition of the sample is 40% Boron and 60% Oxygen
