Ex 7.2, 3 - Chapter 7 Class 9 Triangles

Last updated at August 14, 2026 by

Ex 7.2, 3 - ABC is an isosceles triangle in which altitudes - Ex 7.2

part 2 - Ex 7.2, 3 - Ex 7.2 - Serial order wise - Chapter 7 Class 9 Triangles

 

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Transcript

Ex7.2, 3 ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see the given figure). Show that these altitudes are equal. Given: Given ABC is isosceles with AB & AC equal, i.e. AB = AC BE and CF are altitudes. So, AEB = 90 and AFC = 90 To prove: BE = CF Proof: We take ABE and ACF, In ABE and ACF, AEB = AFC A = A AB = AC ABE ACF BE = CF Hence proved

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