Ex 7.2, 2 - Chapter 7 Class 9 Triangles
Last updated at April 16, 2024 by Teachoo
Opposite Angles of equal sides
Chapter 7 Class 9 Triangles
Concept wise
- Congruency - Introduction
- SAS
- ASA/AAS
-
Opposite Angles of equal sides
- SSS
- RHS
- Side inequality
Transcript
Ex7.2, 2 In ABC, AD is the perpendicular bisector of BC (see the given figure). Show that ABC is an isosceles triangle in which AB = AC. Given: Line AD is perpendicular to BC So, ADC = ADB = 90 & Line AD bisects line BC (as it is perpendicular bisector) BD = CD To prove: ABC is isosceles, i.e. AB = AC Proof: In ABD and ACD, AD = AD ADB = ADC BD = CD ADC ADB AB = AC Therefore, ABC is an isosceles triangle in which AB = AC. Hence proved
