Ex 4.3, 4 - The taxi fare in a city is as follows: For the - Forming Equations and drawing graph

  1. Chapter 4 Class 9 Linear Equations in Two Variables
  2. Serial order wise
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Ex 4.3, 4 The taxi fare in a city is as follows: For the first kilometre, the fares is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph. Total distance covered = x km Fare for 1st kilometre = Rs 8 Fare for the rest of the distance = Rs 5 Remaining distance = Rs 5 (x 1) Total fare = Fare for 1st km + Fare for rest (x 1) km y = 8 + (x 1)5 y = 8 + 5x 5 y = 5x + 3 To draw the graph, we need at least two solutions of the equation. Putting x = 0, y = 5(0) + 3 y = 0 + 3 y = 3 So, (0,3) is a solution of the equation Putting x = 1 , y = 5(1) + 3 y = 5 + 3 y = 8 So, (1,8) is a solution of the equation Plotting points

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.