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Ex 4.3, 4 - The taxi fare in a city is as follows: For the - Forming Equations and drawing graph

Ex 4.3, 4 - Chapter 4 Class 9 Linear Equations in Two Variables - Part 2
Ex 4.3, 4 - Chapter 4 Class 9 Linear Equations in Two Variables - Part 3

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Ex 4.3, 4 The taxi fare in a city is as follows: For the first kilometre, the fares is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph. Total distance covered = x km Fare for 1st kilometre = Rs 8 Fare for the rest of the distance = Rs 5 Remaining distance = Rs 5 (x 1) Total fare = Fare for 1st km + Fare for rest (x 1) km y = 8 + (x 1)5 y = 8 + 5x 5 y = 5x + 3 To draw the graph, we need at least two solutions of the equation. Putting x = 0, y = 5(0) + 3 y = 0 + 3 y = 3 So, (0,3) is a solution of the equation Putting x = 1 , y = 5(1) + 3 y = 5 + 3 y = 8 So, (1,8) is a solution of the equation Plotting points

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.