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Class 9
Chapter 12 Class 9 - Sound

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Example 12.3 A ship sends out ultrasound that returns from the seabed and is detected after 3.42 s. If the speed of ultrasound through seawater is 1531 m/s, what is the distance of the seabed from the ship? Time taken by sound = 3.42 s Speed of ultra sound = 1531 m/s Let distance between seabed and ship = d ∴ Distance travelled by ultrasound = 2 Γ— d We know that, Speed = π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’/π‘‡π‘–π‘šπ‘’ ∴ Distance = Speed Γ— Time 2d = 1531 Γ— 3.42 d = (1531 Γ— 342)/(2 Γ— 100) d = (1531 Γ— 171)/100 d = 261801/100 d = 2618 m Distance between seabed and ship is 2618 m

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Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 13 years and a teacher from the past 17 years. He teaches Science, Economics, Accounting and English at Teachoo