Answers!
y= 1/(10-2logx²)²
y'= {-1/(10-2logx²)³}{(-2/x²)(2x)}
y'=4/x(10-2logx²)³
Ans...
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Answer the question...
y= 1/(10-2logx²)²
y'= {-1/(10-2logx²)³}{(-2/x²)(2x)}
y'=4/x(10-2logx²)³
Ans...
Comment