A circle is touching the side BC of triangle ABC at P and touching AB and AC produced at Q and R respectively. Prove that AO=1÷2 ( perimeter of triangle ABC)
Answers!
AB+CB+CA
AB+BD+PC+AR-CR
AB++BQ+DC+AQ-PC
AQ+AQ
ABC=ZAQ
Comment
Answer the question...
AB+CB+CA
AB+BD+PC+AR-CR
AB++BQ+DC+AQ-PC
AQ+AQ
ABC=ZAQ
AB+BD+PC+AR-CR
AB++BQ+DC+AQ-PC
AQ+AQ
ABC=ZAQ
Comment