On integrating G(x,y,z)= x^2 over the cone z= sqrt(x^2+y^2) ,0 is less

Maths

On integrating G(x,y,z)= x^2 over the cone z= sqrt(x^2+y^2) ,0 is lesser than equal to z is lesser than equal to 1 results obtained is

Meghana M

Oct. 24, 2021, 12:52 p.m.

Class 6