ABCD is a square whose side is a. Taking AB&ADas axes,find equation of circle circumscribing the square ABCD
Answers!
Let the side be a
It start from origin A(0,0)
B=y axis =0,a
D=x axis=a,0
C=a,a
Since AC is diameter
So, x(x-a)+y(y-a)=0 [Diametric form]
Comment
Answer the question...
Let the side be a
It start from origin A(0,0)
B=y axis =0,a
D=x axis=a,0
C=a,a
Since AC is diameter
So, x(x-a)+y(y-a)=0 [Diametric form]
Comment