Evaluate : Integral (1-x) √xdx.
Answers!
I=(x½-x^3/2)dx
=x½ ½/½ ½-x^3/2 3/2/3/2 3/2 c
=x^3/2/3/2-x^5/2/5/2 c
=2x^3/2/3-2x^5/2/5 c.
Comment
Answer the question...
I=(x½-x^3/2)dx
=x½ ½/½ ½-x^3/2 3/2/3/2 3/2 c
=x^3/2/3/2-x^5/2/5/2 c
=2x^3/2/3-2x^5/2/5 c.
=x½ ½/½ ½-x^3/2 3/2/3/2 3/2 c
=x^3/2/3/2-x^5/2/5/2 c
=2x^3/2/3-2x^5/2/5 c.
Comment