Answers!
In ∆SPQ and In ∆RQO
angle spq = rqo
Sp=Rq(becoz || ss of parallelogram are=)
s as angle 1 ,r angle as 2 (1=2)
So triangle congruent by asa
1 2 (crsp angles)
2angle 1 : 180
Angle 1 =180/2
1=90
Comment
Answer the question...
In ∆SPQ and In ∆RQO
angle spq = rqo
Sp=Rq(becoz || ss of parallelogram are=)
s as angle 1 ,r angle as 2 (1=2)
So triangle congruent by asa
1 2 (crsp angles)
2angle 1 : 180
Angle 1 =180/2
1=90
angle spq = rqo
Sp=Rq(becoz || ss of parallelogram are=)
s as angle 1 ,r angle as 2 (1=2)
So triangle congruent by asa
1 2 (crsp angles)
2angle 1 : 180
Angle 1 =180/2
1=90
Comment