Answers!
Sin A = 3/4 = opposite/Adjacent
Using phythgoras theorem
AB = √Ac2 - BC2
AB = √4square - 3square
AB = √16 - 9
AB = √7
Cos A = Adjacent/Hypotenuse = √7/4
Cos A = √7/4
Tan A = Opposite/Adjacent = 3/√7
Hence proved ➕➖✖️➗
- Thanking you
Comment
Answer the question...
Sin A = 3/4 = opposite/Adjacent
Using phythgoras theorem
AB = √Ac2 - BC2
AB = √4square - 3square
AB = √16 - 9
AB = √7
Cos A = Adjacent/Hypotenuse = √7/4
Cos A = √7/4
Tan A = Opposite/Adjacent = 3/√7
Hence proved ➕➖✖️➗
- Thanking you
Comment